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13113202100212 = 223278300525053
BaseRepresentation
bin1011111011010010011111…
…0000001100011111110100
31201102121110121020001100201
42332310213300030133310
53204321314214201322
643520042154250244
72522253241520104
oct276644760143764
951377417201321
1013113202100212
1141a63067a8115
121579514a26984
137417536aaa76
1433497a5bd204
1517b187944d27
hexbed27c0c7f4

13113202100212 has 6 divisors (see below), whose sum is σ = 22948103675378. Its totient is φ = 6556601050104.

The previous prime is 13113202100209. The next prime is 13113202100231. The reversal of 13113202100212 is 21200120231131.

It can be written as a sum of positive squares in only one way, i.e., 12525964953616 + 587237146596 = 3539204^2 + 766314^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13113202100212.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1639150262523 + ... + 1639150262530.

Almost surely, 213113202100212 is an apocalyptic number.

It is an amenable number.

13113202100212 is a deficient number, since it is larger than the sum of its proper divisors (9834901575166).

13113202100212 is a wasteful number, since it uses less digits than its factorization.

13113202100212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3278300525057 (or 3278300525055 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13113202100212 its reverse (21200120231131), we get a palindrome (34313322331343).

The spelling of 13113202100212 in words is "thirteen trillion, one hundred thirteen billion, two hundred two million, one hundred thousand, two hundred twelve".

Divisors: 1 2 4 3278300525053 6556601050106 13113202100212