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131132122010341 is a prime number
BaseRepresentation
bin11101110100001110010011…
…100011010001001011100101
3122012022002221001022020211021
4131310032103203101023211
5114141432041213312331
61142521133141411141
736422661141053104
oct3564162343211345
9565262831266737
10131132122010341
11388679032a4001
121285a34a409ab1
13582292424b86a
142454b8584a03b
1510260aa0d7211
hex7743938d12e5

131132122010341 has 2 divisors, whose sum is σ = 131132122010342. Its totient is φ = 131132122010340.

The previous prime is 131132122010321. The next prime is 131132122010347. The reversal of 131132122010341 is 143010221231131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121731281576100 + 9400840434241 = 11033190^2 + 3066079^2 .

It is a cyclic number.

It is not a de Polignac number, because 131132122010341 - 213 = 131132122002149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131132122010347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566061005170 + 65566061005171.

It is an arithmetic number, because the mean of its divisors is an integer number (65566061005171).

Almost surely, 2131132122010341 is an apocalyptic number.

It is an amenable number.

131132122010341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131132122010341 is an equidigital number, since it uses as much as digits as its factorization.

131132122010341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131132122010341 its reverse (143010221231131), we get a palindrome (274142343241472).

The spelling of 131132122010341 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, one hundred twenty-two million, ten thousand, three hundred forty-one".