Base | Representation |
---|---|
bin | 11101110100001110011001… |
… | …011101110001100001101111 |
3 | 122012022010011222000022002022 |
4 | 131310032121131301201233 |
5 | 114141432242113431023 |
6 | 1142521151044220355 |
7 | 36422663454330545 |
oct | 3564163135614157 |
9 | 565263158008068 |
10 | 131132221233263 |
11 | 38867954304718 |
12 | 1285a37769a6bb |
13 | 582293b97c753 |
14 | 2454b94ab7d95 |
15 | 10260b3b867c8 |
hex | 77439977186f |
131132221233263 has 2 divisors, whose sum is σ = 131132221233264. Its totient is φ = 131132221233262.
The previous prime is 131132221233257. The next prime is 131132221233271. The reversal of 131132221233263 is 362332122231131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131132221233263 - 26 = 131132221233199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131132226233263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566110616631 + 65566110616632.
It is an arithmetic number, because the mean of its divisors is an integer number (65566110616632).
Almost surely, 2131132221233263 is an apocalyptic number.
131132221233263 is a deficient number, since it is larger than the sum of its proper divisors (1).
131132221233263 is an equidigital number, since it uses as much as digits as its factorization.
131132221233263 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 46656, while the sum is 35.
Adding to 131132221233263 its reverse (362332122231131), we get a palindrome (493464343464394).
The spelling of 131132221233263 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, two hundred twenty-one million, two hundred thirty-three thousand, two hundred sixty-three".
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