13113222130 has 8 divisors (see below), whose sum is σ = 23603799852. Its totient is φ = 5245288848.

The previous prime is 13113222113. The next prime is 13113222131. The reversal of 13113222130 is 3122231131.

It can be written as a sum of positive squares in 2 ways, for example, as 11187504441 + 1925717689 = 105771^2 + 43883^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×13113222130³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13113222098 and 13113222107.

It is not an unprimeable number, because it can be changed into a prime (13113222131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655661097 + ... + 655661116.

Almost surely, 2^13113222130 is an apocalyptic number.

13113222130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13113222130 is a deficient number, since it is larger than the sum of its proper divisors (10490577722).

13113222130 is a wasteful number, since it uses less digits than its factorization.

13113222130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1311322220.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13113222130 its reverse (3122231131), we get a palindrome (16235453261).

Subtracting from 13113222130 its reverse (3122231131), we obtain a palindrome (9990990999).

The spelling of 13113222130 in words is "thirteen billion, one hundred thirteen million, two hundred twenty-two thousand, one hundred thirty".