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131132301102000 = 2432531119376311493
BaseRepresentation
bin11101110100001110011110…
…001110011100101110110000
3122012022010101112022001101200
4131310032132032130232300
5114141432423040231000
61142521203020131200
736422665444236162
oct3564163616345660
9565263345261350
10131132301102000
11388679953a6240
121285a39a396b00
135822952395163
142454ba1548932
1510260babb1500
hex77439e39cbb0

131132301102000 has 1920 divisors, whose sum is σ = 541367473121280. Its totient is φ = 29236515840000.

The previous prime is 131132301101987. The next prime is 131132301102001. The reversal of 131132301102000 is 201103231131.

131132301102000 is a `hidden beast` number, since 1 + 31 + 1 + 323 + 0 + 110 + 200 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (131132301102001) by changing a digit.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 87831413254 + ... + 87831414746.

It is an arithmetic number, because the mean of its divisors is an integer number (281962225584).

Almost surely, 2131132301102000 is an apocalyptic number.

131132301102000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131132301102000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (270683736560640).

131132301102000 is an abundant number, since it is smaller than the sum of its proper divisors (410235172019280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131132301102000 is a wasteful number, since it uses less digits than its factorization.

131132301102000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2220 (or 2201 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 131132301102000 its reverse (201103231131), we get a palindrome (131333404333131).

The spelling of 131132301102000 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, three hundred one million, one hundred two thousand".