13113243015181 has 2 divisors, whose sum is σ = 13113243015182. Its totient is φ = 13113243015180.

The previous prime is 13113243015149. The next prime is 13113243015251. The reversal of 13113243015181 is 18151034231131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11521883472100 + 1591359543081 = 3394390^2 + 1261491^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113243015181 - 2⁵ = 13113243015149 is a prime.

It is a super-2 number, since 2×13113243015181² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113243015101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556621507590 + 6556621507591.

It is an arithmetic number, because the mean of its divisors is an integer number (6556621507591).

Almost surely, 2^{13113243015181} is an apocalyptic number.

It is an amenable number.

13113243015181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113243015181 is an equidigital number, since it uses as much as digits as its factorization.

13113243015181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 34.

The spelling of 13113243015181 in words is "thirteen trillion, one hundred thirteen billion, two hundred forty-three million, fifteen thousand, one hundred eighty-one".