Base | Representation |
---|---|
bin | 1011111011010010110110… |
… | …0101101100010000000101 |
3 | 1201102121201102110101022202 |
4 | 2332310231211230100011 |
5 | 3204322014300304424 |
6 | 43520100013004245 |
7 | 2522255540655254 |
oct | 276645545542005 |
9 | 51377642411282 |
10 | 13113300009989 |
11 | 41a6356aa1193 |
12 | 1579541783685 |
13 | 74176aa6c04a |
14 | 3349895c879b |
15 | 17b1913352ae |
hex | bed2d96c405 |
13113300009989 has 2 divisors, whose sum is σ = 13113300009990. Its totient is φ = 13113300009988.
The previous prime is 13113300009967. The next prime is 13113300010081. The reversal of 13113300009989 is 98990000331131.
13113300009989 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8808774689764 + 4304525320225 = 2967958^2 + 2074735^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13113300009989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113300009919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556650004994 + 6556650004995.
It is an arithmetic number, because the mean of its divisors is an integer number (6556650004995).
Almost surely, 213113300009989 is an apocalyptic number.
It is an amenable number.
13113300009989 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113300009989 is an equidigital number, since it uses as much as digits as its factorization.
13113300009989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 157464, while the sum is 47.
The spelling of 13113300009989 in words is "thirteen trillion, one hundred thirteen billion, three hundred million, nine thousand, nine hundred eighty-nine".
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