Base | Representation |
---|---|
bin | 11000011011001110… |
… | …10011101011101011 |
3 | 1020211220000011110121 |
4 | 30031213103223223 |
5 | 203324001404211 |
6 | 10005115424111 |
7 | 642650203201 |
oct | 141547235353 |
9 | 36756004417 |
10 | 13113309931 |
11 | 561a137927 |
12 | 265b755037 |
13 | 130c9c57b7 |
14 | 8c5823071 |
15 | 51b385271 |
hex | 30d9d3aeb |
13113309931 has 2 divisors, whose sum is σ = 13113309932. Its totient is φ = 13113309930.
The previous prime is 13113309899. The next prime is 13113310003. The reversal of 13113309931 is 13990331131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13113309931 - 25 = 13113309899 is a prime.
It is a super-2 number, since 2×131133099312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13113304931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556654965 + 6556654966.
It is an arithmetic number, because the mean of its divisors is an integer number (6556654966).
Almost surely, 213113309931 is an apocalyptic number.
13113309931 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113309931 is an equidigital number, since it uses as much as digits as its factorization.
13113309931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6561, while the sum is 34.
The spelling of 13113309931 in words is "thirteen billion, one hundred thirteen million, three hundred nine thousand, nine hundred thirty-one".
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