Base | Representation |
---|---|
bin | 11101110100001111001110… |
… | …101000101100111001100111 |
3 | 122012022012111010120111100102 |
4 | 131310033032220230321213 |
5 | 114141441104000242333 |
6 | 1142521415352134315 |
7 | 36423024535565213 |
oct | 3564171650547147 |
9 | 565265433514312 |
10 | 131133113290343 |
11 | 3886827190137a |
12 | 1285a58639739b |
13 | 5822a51724988 |
14 | 2454c3b367943 |
15 | 1026117144ae8 |
hex | 7743cea2ce67 |
131133113290343 has 2 divisors, whose sum is σ = 131133113290344. Its totient is φ = 131133113290342.
The previous prime is 131133113290253. The next prime is 131133113290349. The reversal of 131133113290343 is 343092311331131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131133113290343 - 28 = 131133113290087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131133113290297 and 131133113290306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131133113290349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566556645171 + 65566556645172.
It is an arithmetic number, because the mean of its divisors is an integer number (65566556645172).
Almost surely, 2131133113290343 is an apocalyptic number.
131133113290343 is a deficient number, since it is larger than the sum of its proper divisors (1).
131133113290343 is an equidigital number, since it uses as much as digits as its factorization.
131133113290343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52488, while the sum is 38.
The spelling of 131133113290343 in words is "one hundred thirty-one trillion, one hundred thirty-three billion, one hundred thirteen million, two hundred ninety thousand, three hundred forty-three".
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