Base | Representation |
---|---|
bin | 11000011011001111… |
… | …01100101100110001 |
3 | 1020211220012101000210 |
4 | 30031213230230301 |
5 | 203324013144101 |
6 | 10005121534333 |
7 | 642651111015 |
oct | 141547545461 |
9 | 36756171023 |
10 | 13113412401 |
11 | 561a1a7911 |
12 | 265b7a43a9 |
13 | 130ca3032b |
14 | 8c584c545 |
15 | 51b3a57d6 |
hex | 30d9ecb31 |
13113412401 has 4 divisors (see below), whose sum is σ = 17484549872. Its totient is φ = 8742274932.
The previous prime is 13113412399. The next prime is 13113412427. The reversal of 13113412401 is 10421431131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10421431131 = 3 ⋅3473810377.
It is not a de Polignac number, because 13113412401 - 21 = 13113412399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13113412201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185568731 + ... + 2185568736.
It is an arithmetic number, because the mean of its divisors is an integer number (4371137468).
Almost surely, 213113412401 is an apocalyptic number.
It is an amenable number.
13113412401 is a deficient number, since it is larger than the sum of its proper divisors (4371137471).
13113412401 is an equidigital number, since it uses as much as digits as its factorization.
13113412401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4371137470.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13113412401 its reverse (10421431131), we get a palindrome (23534843532).
The spelling of 13113412401 in words is "thirteen billion, one hundred thirteen million, four hundred twelve thousand, four hundred one".
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