13113420233 has 4 divisors (see below), whose sum is σ = 13113662208. Its totient is φ = 13113178260.

The previous prime is 13113420191. The next prime is 13113420251. The reversal of 13113420233 is 33202431131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33202431131 = 17231 ⋅1926901.

It is a cyclic number.

It is not a de Polignac number, because 13113420233 - 2¹⁸ = 13113158089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13113420199 and 13113420208.

It is not an unprimeable number, because it can be changed into a prime (13113420533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1928 + ... + 161958.

It is an arithmetic number, because the mean of its divisors is an integer number (3278415552).

Almost surely, 2^13113420233 is an apocalyptic number.

It is an amenable number.

13113420233 is a deficient number, since it is larger than the sum of its proper divisors (241975).

13113420233 is an equidigital number, since it uses as much as digits as its factorization.

13113420233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 241974.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13113420233 its reverse (33202431131), we get a palindrome (46315851364).

The spelling of 13113420233 in words is "thirteen billion, one hundred thirteen million, four hundred twenty thousand, two hundred thirty-three".