Base | Representation |
---|---|
bin | 1011111011010011010100… |
… | …0010101011101000001011 |
3 | 1201102122001010202002010211 |
4 | 2332310311002223220023 |
5 | 3204322243303100443 |
6 | 43520120241021551 |
7 | 2522261616540616 |
oct | 276646502535013 |
9 | 51378033662124 |
10 | 13113425050123 |
11 | 41a6410635742 |
12 | 15795776248b7 |
13 | 74178a93c0a8 |
14 | 33499c05717d |
15 | 17b19c2d419d |
hex | bed350aba0b |
13113425050123 has 2 divisors, whose sum is σ = 13113425050124. Its totient is φ = 13113425050122.
The previous prime is 13113425050111. The next prime is 13113425050127. The reversal of 13113425050123 is 32105052431131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113425050123 - 217 = 13113424919051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13113425050127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556712525061 + 6556712525062.
It is an arithmetic number, because the mean of its divisors is an integer number (6556712525062).
Almost surely, 213113425050123 is an apocalyptic number.
13113425050123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113425050123 is an equidigital number, since it uses as much as digits as its factorization.
13113425050123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13113425050123 its reverse (32105052431131), we get a palindrome (45218477481254).
The spelling of 13113425050123 in words is "thirteen trillion, one hundred thirteen billion, four hundred twenty-five million, fifty thousand, one hundred twenty-three".
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