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13113431143 is a prime number
BaseRepresentation
bin11000011011001111…
…10001010001100111
31020211220020022201221
430031213301101213
5203324014244033
610005122201211
7642651216451
oct141547612147
936756208657
1013113431143
11561a20a9aa
12265b7b3207
13130ca38a17
148c58552d1
1551b3ab12d
hex30d9f1467

13113431143 has 2 divisors, whose sum is σ = 13113431144. Its totient is φ = 13113431142.

The previous prime is 13113431129. The next prime is 13113431159. The reversal of 13113431143 is 34113431131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13113431143 - 213 = 13113422951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113461143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556715571 + 6556715572.

It is an arithmetic number, because the mean of its divisors is an integer number (6556715572).

Almost surely, 213113431143 is an apocalyptic number.

13113431143 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113431143 is an equidigital number, since it uses as much as digits as its factorization.

13113431143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 13113431143 its reverse (34113431131), we get a palindrome (47226862274).

The spelling of 13113431143 in words is "thirteen billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred forty-three".