Search a number
-
+
13113433 = 88314851
BaseRepresentation
bin110010000001…
…100001011001
3220200020020201
4302001201121
511324112213
61145022201
7216314404
oct62014131
926606221
1013113433
117447353
124484961
132941a38
141a54d3b
1512406dd
hexc81859

13113433 has 4 divisors (see below), whose sum is σ = 13129168. Its totient is φ = 13097700.

The previous prime is 13113431. The next prime is 13113467. The reversal of 13113433 is 33431131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13113433 - 21 = 13113431 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13113433.

It is not an unprimeable number, because it can be changed into a prime (13113431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6543 + ... + 8308.

It is an arithmetic number, because the mean of its divisors is an integer number (3282292).

Almost surely, 213113433 is an apocalyptic number.

It is an amenable number.

13113433 is a deficient number, since it is larger than the sum of its proper divisors (15735).

13113433 is an equidigital number, since it uses as much as digits as its factorization.

13113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15734.

The product of its digits is 324, while the sum is 19.

The square root of 13113433 is about 3621.2474370029. The cubic root of 13113433 is about 235.8153839622.

Adding to 13113433 its reverse (33431131), we get a palindrome (46544564).

The spelling of 13113433 in words is "thirteen million, one hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 883 14851 13113433