13113440131 has 8 divisors (see below), whose sum is σ = 14311987200. Its totient is φ = 11915962440.

The previous prime is 13113440113. The next prime is 13113440143. The reversal of 13113440131 is 13104431131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13113440131 - 2⁵ = 13113440099 is a prime.

It is a super-2 number, since 2×13113440131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13113449131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 241591 + ... + 290848.

It is an arithmetic number, because the mean of its divisors is an integer number (1788998400).

Almost surely, 2^13113440131 is an apocalyptic number.

13113440131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13113440131 is a deficient number, since it is larger than the sum of its proper divisors (1198547069).

13113440131 is a wasteful number, since it uses less digits than its factorization.

13113440131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 534689.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13113440131 its reverse (13104431131), we get a palindrome (26217871262).

The spelling of 13113440131 in words is "thirteen billion, one hundred thirteen million, four hundred forty thousand, one hundred thirty-one".