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1311345131497 is a prime number
BaseRepresentation
bin10011000101010010010…
…000101011111111101001
311122100210220012211212121
4103011102100223333221
5132441113323201442
62442231301111241
7163512232463452
oct23052220537751
94570726184777
101311345131497
1146615815a425
121921929b8521
1396875691cbb
144768021a129
152419ee3a967
hex1315242bfe9

1311345131497 has 2 divisors, whose sum is σ = 1311345131498. Its totient is φ = 1311345131496.

The previous prime is 1311345131489. The next prime is 1311345131527. The reversal of 1311345131497 is 7941315431131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1287780118416 + 23565013081 = 1134804^2 + 153509^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311345131497 - 23 = 1311345131489 is a prime.

It is a super-2 number, since 2×13113451314972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311345131297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655672565748 + 655672565749.

It is an arithmetic number, because the mean of its divisors is an integer number (655672565749).

Almost surely, 21311345131497 is an apocalyptic number.

It is an amenable number.

1311345131497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311345131497 is an equidigital number, since it uses as much as digits as its factorization.

1311345131497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 136080, while the sum is 43.

The spelling of 1311345131497 in words is "one trillion, three hundred eleven billion, three hundred forty-five million, one hundred thirty-one thousand, four hundred ninety-seven".