1311351002551 has 4 divisors (see below), whose sum is σ = 1311490472872. Its totient is φ = 1311211532232.

The previous prime is 1311351002543. The next prime is 1311351002557. The reversal of 1311351002551 is 1552001531131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311351002551 - 2³ = 1311351002543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311351002557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69721056 + ... + 69739861.

It is an arithmetic number, because the mean of its divisors is an integer number (327872618218).

Almost surely, 2^{1311351002551} is an apocalyptic number.

1311351002551 is a deficient number, since it is larger than the sum of its proper divisors (139470321).

1311351002551 is an equidigital number, since it uses as much as digits as its factorization.

1311351002551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139470320.

The product of its (nonzero) digits is 2250, while the sum is 28.

Adding to 1311351002551 its reverse (1552001531131), we get a palindrome (2863352533682).

The spelling of 1311351002551 in words is "one trillion, three hundred eleven billion, three hundred fifty-one million, two thousand, five hundred fifty-one".