13113641705472 has 1344 divisors, whose sum is σ = 51018549321600. Its totient is φ = 3287820533760.

The previous prime is 13113641705459. The next prime is 13113641705491. The reversal of 13113641705472 is 27450714631131.

13113641705472 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 3 + 6 + 4 + 170 + 5 + 472 = 666.

It is a tau number, because it is divible by the number of its divisors (1344).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3457325208 + ... + 3457329000.

It is an arithmetic number, because the mean of its divisors is an integer number (37960230150).

Almost surely, 2^{13113641705472} is an apocalyptic number.

13113641705472 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113641705472, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25509274660800).

13113641705472 is an abundant number, since it is smaller than the sum of its proper divisors (37904907616128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113641705472 is a wasteful number, since it uses less digits than its factorization.

13113641705472 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3882 (or 3845 counting only the distinct ones).

The product of its (nonzero) digits is 423360, while the sum is 45.

The spelling of 13113641705472 in words is "thirteen trillion, one hundred thirteen billion, six hundred forty-one million, seven hundred five thousand, four hundred seventy-two".