Base | Representation |
---|---|
bin | 11101110100010101111100… |
… | …001101101110101010011011 |
3 | 122012022220002102001202010002 |
4 | 131310111330031232222123 |
5 | 114142100334012010210 |
6 | 1142525010450043215 |
7 | 36423401251315403 |
oct | 3564257415565233 |
9 | 565286072052102 |
10 | 131140320422555 |
11 | 3887033006a494 |
12 | 1285ba57b7950b |
13 | 582362c911352 |
14 | 2455322601803 |
15 | 10263d9c264a5 |
hex | 77457c36ea9b |
131140320422555 has 8 divisors (see below), whose sum is σ = 157372958976912. Its totient is φ = 104909206691488.
The previous prime is 131140320422549. The next prime is 131140320422563. The reversal of 131140320422555 is 555224023041131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131140320422555 - 26 = 131140320422491 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 381016604 + ... + 381360633.
It is an arithmetic number, because the mean of its divisors is an integer number (19671619872114).
Almost surely, 2131140320422555 is an apocalyptic number.
131140320422555 is a deficient number, since it is larger than the sum of its proper divisors (26232638554357).
131140320422555 is an equidigital number, since it uses as much as digits as its factorization.
131140320422555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 762411645.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 131140320422555 its reverse (555224023041131), we get a palindrome (686364343463686).
The spelling of 131140320422555 in words is "one hundred thirty-one trillion, one hundred forty billion, three hundred twenty million, four hundred twenty-two thousand, five hundred fifty-five".
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