Base | Representation |
---|---|
bin | 10011000101010101111… |
… | …010111101111111010111 |
3 | 11122100222011210001222021 |
4 | 103011111322331333113 |
5 | 132441230034000103 |
6 | 2442241333314011 |
7 | 163513606504225 |
oct | 23052572757727 |
9 | 4570864701867 |
10 | 1311406546903 |
11 | 466189897762 |
12 | 1921ab495907 |
13 | 9688531628b |
14 | 47688445b15 |
15 | 241a551cbbd |
hex | 13155ebdfd7 |
1311406546903 has 2 divisors, whose sum is σ = 1311406546904. Its totient is φ = 1311406546902.
The previous prime is 1311406546871. The next prime is 1311406546921. The reversal of 1311406546903 is 3096456041131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311406546903 - 25 = 1311406546871 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1311406546903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311406546973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655703273451 + 655703273452.
It is an arithmetic number, because the mean of its divisors is an integer number (655703273452).
Almost surely, 21311406546903 is an apocalyptic number.
1311406546903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311406546903 is an equidigital number, since it uses as much as digits as its factorization.
1311406546903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 43.
The spelling of 1311406546903 in words is "one trillion, three hundred eleven billion, four hundred six million, five hundred forty-six thousand, nine hundred three".
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