131141100014011 has 4 divisors (see below), whose sum is σ = 131141124500800. Its totient is φ = 131141075527224.

The previous prime is 131141100013999. The next prime is 131141100014033. The reversal of 131141100014011 is 110410001141131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131141100014011 - 2³⁹ = 130591344200123 is a prime.

It is a super-2 number, since 2×131141100014011² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131141100014011.

It is not an unprimeable number, because it can be changed into a prime (131141100018011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 375156 + ... + 16199473.

It is an arithmetic number, because the mean of its divisors is an integer number (32785281125200).

Almost surely, 2^{131141100014011} is an apocalyptic number.

131141100014011 is a deficient number, since it is larger than the sum of its proper divisors (24486789).

131141100014011 is an equidigital number, since it uses as much as digits as its factorization.

131141100014011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24486788.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 131141100014011 its reverse (110410001141131), we get a palindrome (241551101155142).

The spelling of 131141100014011 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, fourteen thousand, eleven".