Base | Representation |
---|---|
bin | 11101110100010110101010… |
… | …101100110000110111011111 |
3 | 122012022222002202120010112122 |
4 | 131310112222230300313133 |
5 | 114142103433134404413 |
6 | 1142525220105453155 |
7 | 36423426501253601 |
oct | 3564265254606737 |
9 | 565288082503478 |
10 | 131141100309983 |
11 | 388706a0313455 |
12 | 128600351a11bb |
13 | 58237253717ba |
14 | 2455398013171 |
15 | 1026433429108 |
hex | 7745aab30ddf |
131141100309983 has 2 divisors, whose sum is σ = 131141100309984. Its totient is φ = 131141100309982.
The previous prime is 131141100309979. The next prime is 131141100310063. The reversal of 131141100309983 is 389903001141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141100309983 - 22 = 131141100309979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141100300983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570550154991 + 65570550154992.
It is an arithmetic number, because the mean of its divisors is an integer number (65570550154992).
Almost surely, 2131141100309983 is an apocalyptic number.
131141100309983 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141100309983 is an equidigital number, since it uses as much as digits as its factorization.
131141100309983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 44.
The spelling of 131141100309983 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, three hundred nine thousand, nine hundred eighty-three".
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