Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …010110101011111110101011 |
3 | 122012022222010112020111000201 |
4 | 131310112223112223332223 |
5 | 114142103443443100021 |
6 | 1142525221141213031 |
7 | 36423426663545521 |
oct | 3564265326537653 |
9 | 565288115214021 |
10 | 131141111300011 |
11 | 388706a653a41a |
12 | 12860038a01177 |
13 | 582372771bb87 |
14 | 2455399674311 |
15 | 102643439a591 |
hex | 7745ab5abfab |
131141111300011 has 2 divisors, whose sum is σ = 131141111300012. Its totient is φ = 131141111300010.
The previous prime is 131141111299967. The next prime is 131141111300047. The reversal of 131141111300011 is 110003111141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131141111300011 - 243 = 122345018277803 is a prime.
It is not a weakly prime, because it can be changed into another prime (131141115300011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570555650005 + 65570555650006.
It is an arithmetic number, because the mean of its divisors is an integer number (65570555650006).
Almost surely, 2131141111300011 is an apocalyptic number.
131141111300011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141111300011 is an equidigital number, since it uses as much as digits as its factorization.
131141111300011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 19.
Adding to 131141111300011 its reverse (110003111141131), we get a palindrome (241144222441142).
The spelling of 131141111300011 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, three hundred thousand, eleven".
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