Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …010110101011111101111111 |
3 | 122012022222010112020110222002 |
4 | 131310112223112223331333 |
5 | 114142103443443044332 |
6 | 1142525221141212515 |
7 | 36423426663545426 |
oct | 3564265326537577 |
9 | 565288115213862 |
10 | 131141111299967 |
11 | 388706a653a38a |
12 | 12860038a0113b |
13 | 582372771bb52 |
14 | 24553996742bd |
15 | 102643439a562 |
hex | 7745ab5abf7f |
131141111299967 has 2 divisors, whose sum is σ = 131141111299968. Its totient is φ = 131141111299966.
The previous prime is 131141111299901. The next prime is 131141111300011. The reversal of 131141111299967 is 769992111141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131141111299967 - 212 = 131141111295871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141111299567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570555649983 + 65570555649984.
It is an arithmetic number, because the mean of its divisors is an integer number (65570555649984).
Almost surely, 2131141111299967 is an apocalyptic number.
131141111299967 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141111299967 is an equidigital number, since it uses as much as digits as its factorization.
131141111299967 is an evil number, because the sum of its binary digits is even.
The product of its digits is 734832, while the sum is 56.
The spelling of 131141111299967 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred ninety-nine thousand, nine hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •