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131141124034369 is a prime number
BaseRepresentation
bin11101110100010110101100…
…000111010000111101000001
3122012022222011102012110021121
4131310112230013100331001
5114142104010223044434
61142525222314152241
736423430210024111
oct3564265407207501
9565288142173247
10131141124034369
1138870702747989
1212860041122681
13582372a25a1b7
14245539b22b041
1510264355637b4
hex7745ac1d0f41

131141124034369 has 2 divisors, whose sum is σ = 131141124034370. Its totient is φ = 131141124034368.

The previous prime is 131141124034331. The next prime is 131141124034381. The reversal of 131141124034369 is 963430421141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120523334369344 + 10617789665025 = 10978312^2 + 3258495^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141124034369 - 241 = 128942100778817 is a prime.

It is a super-2 number, since 2×1311411240343692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131141124031369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570562017184 + 65570562017185.

It is an arithmetic number, because the mean of its divisors is an integer number (65570562017185).

Almost surely, 2131141124034369 is an apocalyptic number.

It is an amenable number.

131141124034369 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141124034369 is an equidigital number, since it uses as much as digits as its factorization.

131141124034369 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 43.

The spelling of 131141124034369 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-four million, thirty-four thousand, three hundred sixty-nine".