Base | Representation |
---|---|
bin | 10011000101010110001… |
… | …101100001010001101111 |
3 | 11122100222111221010221010 |
4 | 103011112031201101233 |
5 | 132441232310110111 |
6 | 2442242025440303 |
7 | 163513666030362 |
oct | 23052615412157 |
9 | 4570874833833 |
10 | 1311411410031 |
11 | 466191609478 |
12 | 1921b1040093 |
13 | 96886329978 |
14 | 47688d500d9 |
15 | 241a5b7daa6 |
hex | 1315636146f |
1311411410031 has 4 divisors (see below), whose sum is σ = 1748548546712. Its totient is φ = 874274273352.
The previous prime is 1311411409967. The next prime is 1311411410041. The reversal of 1311411410031 is 1300141141131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1311411410031 - 26 = 1311411409967 is a prime.
It is a super-2 number, since 2×13114114100312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311411410041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218568568336 + ... + 218568568341.
It is an arithmetic number, because the mean of its divisors is an integer number (437137136678).
Almost surely, 21311411410031 is an apocalyptic number.
1311411410031 is a deficient number, since it is larger than the sum of its proper divisors (437137136681).
1311411410031 is an equidigital number, since it uses as much as digits as its factorization.
1311411410031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437137136680.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 1311411410031 its reverse (1300141141131), we get a palindrome (2611552551162).
The spelling of 1311411410031 in words is "one trillion, three hundred eleven billion, four hundred eleven million, four hundred ten thousand, thirty-one".
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