1311412032 has 280 divisors, whose sum is σ = 4514209920. Its totient is φ = 368686080.

The previous prime is 1311412031. The next prime is 1311412093. The reversal of 1311412032 is 2302141131.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1311411996 and 1311412014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311412031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2576194 + ... + 2576702.

Almost surely, 2^1311412032 is an apocalyptic number.

1311412032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311412032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2257104960).

1311412032 is an abundant number, since it is smaller than the sum of its proper divisors (3202797888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311412032 is an equidigital number, since it uses as much as digits as its factorization.

1311412032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 611 (or 592 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 1311412032 is about 36213.4233675857. The cubic root of 1311412032 is about 1094.5771758394.

Adding to 1311412032 its reverse (2302141131), we get a palindrome (3613553163).

The spelling of 1311412032 in words is "one billion, three hundred eleven million, four hundred twelve thousand, thirty-two".