Base | Representation |
---|---|
bin | 11101110100010110110111… |
… | …011101100000001011111111 |
3 | 122012022222122200102201002112 |
4 | 131310112313131200023333 |
5 | 114142104402442211221 |
6 | 1142525253234444235 |
7 | 36423435011150546 |
oct | 3564266735401377 |
9 | 565288580381075 |
10 | 131141314413311 |
11 | 388707a0159454 |
12 | 12860094a3367b |
13 | 582375a826267 |
14 | 24553b862715d |
15 | 102644711c15b |
hex | 7745b77602ff |
131141314413311 has 2 divisors, whose sum is σ = 131141314413312. Its totient is φ = 131141314413310.
The previous prime is 131141314413281. The next prime is 131141314413323. The reversal of 131141314413311 is 113314413141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131141314413311 - 26 = 131141314413247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141314410311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570657206655 + 65570657206656.
It is an arithmetic number, because the mean of its divisors is an integer number (65570657206656).
Almost surely, 2131141314413311 is an apocalyptic number.
131141314413311 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141314413311 is an equidigital number, since it uses as much as digits as its factorization.
131141314413311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 32.
Adding to 131141314413311 its reverse (113314413141131), we get a palindrome (244455727554442).
The spelling of 131141314413311 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred fourteen million, four hundred thirteen thousand, three hundred eleven".
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