Base | Representation |
---|---|
bin | 1011111011010101111100… |
… | …1101000000011111110111 |
3 | 1201102200212102202011220211 |
4 | 2332311133031000133313 |
5 | 3204330220343300434 |
6 | 43520314350010251 |
7 | 2522315266113532 |
oct | 276653715003767 |
9 | 51380772664824 |
10 | 13114132400119 |
11 | 41a6743945213 |
12 | 15797344a6987 |
13 | 741871352a9a |
14 | 334a27d85a19 |
15 | 17b1de459464 |
hex | bed5f3407f7 |
13114132400119 has 2 divisors, whose sum is σ = 13114132400120. Its totient is φ = 13114132400118.
The previous prime is 13114132400107. The next prime is 13114132400123. The reversal of 13114132400119 is 91100423141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114132400119 - 211 = 13114132398071 is a prime.
It is a super-2 number, since 2×131141324001192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114132400219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066200059 + 6557066200060.
It is an arithmetic number, because the mean of its divisors is an integer number (6557066200060).
Almost surely, 213114132400119 is an apocalyptic number.
13114132400119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114132400119 is an equidigital number, since it uses as much as digits as its factorization.
13114132400119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 13114132400119 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thousand, one hundred nineteen".
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