Base | Representation |
---|---|
bin | 111101000100010100… |
… | …0011100110011100011 |
3 | 110112111110112111211012 |
4 | 1322020220130303203 |
5 | 4122034134332003 |
6 | 140125005411135 |
7 | 12321542601404 |
oct | 1721050346343 |
9 | 415443474735 |
10 | 131141324003 |
11 | 50686949808 |
12 | 214bab69aab |
13 | c49c493891 |
14 | 64c0cc39ab |
15 | 362815d8d8 |
hex | 1e88a1cce3 |
131141324003 has 2 divisors, whose sum is σ = 131141324004. Its totient is φ = 131141324002.
The previous prime is 131141323991. The next prime is 131141324029. The reversal of 131141324003 is 300423141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141324003 - 218 = 131141061859 is a prime.
It is a super-2 number, since 2×1311413240032 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131141324003.
It is not a weakly prime, because it can be changed into another prime (131141324803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662001 + 65570662002.
It is an arithmetic number, because the mean of its divisors is an integer number (65570662002).
Almost surely, 2131141324003 is an apocalyptic number.
131141324003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141324003 is an equidigital number, since it uses as much as digits as its factorization.
131141324003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 131141324003 its reverse (300423141131), we get a palindrome (431564465134).
The spelling of 131141324003 in words is "one hundred thirty-one billion, one hundred forty-one million, three hundred twenty-four thousand, three".
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