Base | Representation |
---|---|
bin | 11101110100010110111000… |
… | …000011000000010110110001 |
3 | 122012022222200100221011210222 |
4 | 131310112320003000112301 |
5 | 114142104413001310101 |
6 | 1142525254225302425 |
7 | 36423435160544612 |
oct | 3564267003002661 |
9 | 565288610834728 |
10 | 131141324244401 |
11 | 388707a5763719 |
12 | 12860098194a15 |
13 | 582375c888c83 |
14 | 24553b9a65c09 |
15 | 1026447e1001b |
hex | 7745b80c05b1 |
131141324244401 has 8 divisors (see below), whose sum is σ = 131446769534784. Its totient is φ = 130836229841520.
The previous prime is 131141324244367. The next prime is 131141324244407. The reversal of 131141324244401 is 104442423141131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131141324244401 - 218 = 131141323982257 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131141324244407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86973515 + ... + 88468496.
It is an arithmetic number, because the mean of its divisors is an integer number (16430846191848).
Almost surely, 2131141324244401 is an apocalyptic number.
It is an amenable number.
131141324244401 is a deficient number, since it is larger than the sum of its proper divisors (305445290383).
131141324244401 is an equidigital number, since it uses as much as digits as its factorization.
131141324244401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175443751.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 131141324244401 its reverse (104442423141131), we get a palindrome (235583747385532).
The spelling of 131141324244401 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, two hundred forty-four thousand, four hundred one".
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