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13114134020387 is a prime number
BaseRepresentation
bin1011111011010101111101…
…0011001100000100100011
31201102200212112210111111202
42332311133103030010203
53204330221302123022
643520314444431415
72522315315642411
oct276653723140443
951380775714452
1013114134020387
1141a6744851584
121579734b4856b
1374187179c41a
14334a282882b1
1517b1de679592
hexbed5f4cc123

13114134020387 has 2 divisors, whose sum is σ = 13114134020388. Its totient is φ = 13114134020386.

The previous prime is 13114134020381. The next prime is 13114134020441. The reversal of 13114134020387 is 78302043141131.

It is a weak prime.

It is an emirp because it is prime and its reverse (78302043141131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13114134020387 - 228 = 13113865584931 is a prime.

It is a super-2 number, since 2×131141340203872 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13114134020387.

It is not a weakly prime, because it can be changed into another prime (13114134020381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067010193 + 6557067010194.

It is an arithmetic number, because the mean of its divisors is an integer number (6557067010194).

Almost surely, 213114134020387 is an apocalyptic number.

13114134020387 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114134020387 is an equidigital number, since it uses as much as digits as its factorization.

13114134020387 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 38.

The spelling of 13114134020387 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, twenty thousand, three hundred eighty-seven".