13114134020441 has 2 divisors, whose sum is σ = 13114134020442. Its totient is φ = 13114134020440.

The previous prime is 13114134020387. The next prime is 13114134020587. The reversal of 13114134020441 is 14402043141131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13111061646400 + 3072374041 = 3620920^2 + 55429^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114134020441 - 2¹⁴ = 13114134004057 is a prime.

It is a super-2 number, since 2×13114134020441² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13114134050441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067010220 + 6557067010221.

It is an arithmetic number, because the mean of its divisors is an integer number (6557067010221).

Almost surely, 2^{13114134020441} is an apocalyptic number.

It is an amenable number.

13114134020441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114134020441 is an equidigital number, since it uses as much as digits as its factorization.

13114134020441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 13114134020441 its reverse (14402043141131), we get a palindrome (27516177161572).

The spelling of 13114134020441 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, twenty thousand, four hundred forty-one".