131141340500441 has 2 divisors, whose sum is σ = 131141340500442. Its totient is φ = 131141340500440.

The previous prime is 131141340500407. The next prime is 131141340500473. The reversal of 131141340500441 is 144005043141131.

It is an a-pointer prime, because the next prime (131141340500473) can be obtained adding 131141340500441 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111383137700041 + 19758202800400 = 10553821^2 + 4445020^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141340500441 - 2¹⁴ = 131141340484057 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131141340500398 and 131141340500407.

It is not a weakly prime, because it can be changed into another prime (131141340500491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570670250220 + 65570670250221.

It is an arithmetic number, because the mean of its divisors is an integer number (65570670250221).

Almost surely, 2^{131141340500441} is an apocalyptic number.

It is an amenable number.

131141340500441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141340500441 is an equidigital number, since it uses as much as digits as its factorization.

131141340500441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 131141340500441 its reverse (144005043141131), we get a palindrome (275146383641572).

The spelling of 131141340500441 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty million, five hundred thousand, four hundred forty-one".