Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000010111101100111110011 |
3 | 122012022222201112110222110121 |
4 | 131310112321002331213303 |
5 | 114142104431244313134 |
6 | 1142525300024511111 |
7 | 36423435453214255 |
oct | 3564267102754763 |
9 | 565288645428417 |
10 | 131141341010419 |
11 | 38870804175233 |
12 | 128600a191b497 |
13 | 58237631a93ac |
14 | 24553bbd8bcd5 |
15 | 1026449622ab4 |
hex | 7745b90bd9f3 |
131141341010419 has 4 divisors (see below), whose sum is σ = 131147709279496. Its totient is φ = 131134972741344.
The previous prime is 131141341010341. The next prime is 131141341010501. The reversal of 131141341010419 is 914010143141131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131141341010419 - 213 = 131141341002227 is a prime.
It is a super-2 number, since 2×1311413410104192 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131141341016419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3184103649 + ... + 3184144834.
It is an arithmetic number, because the mean of its divisors is an integer number (32786927319874).
Almost surely, 2131141341010419 is an apocalyptic number.
131141341010419 is a deficient number, since it is larger than the sum of its proper divisors (6368269077).
131141341010419 is an equidigital number, since it uses as much as digits as its factorization.
131141341010419 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6368269076.
The product of its (nonzero) digits is 5184, while the sum is 34.
The spelling of 131141341010419 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, ten thousand, four hundred nineteen".
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