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131141341010341 is a prime number
BaseRepresentation
bin11101110100010110111001…
…000010111101100110100101
3122012022222201112110222100201
4131310112321002331212211
5114142104431244312331
61142525300024510501
736423435453214114
oct3564267102754645
9565288645428321
10131141341010341
1138870804175172
12128600a191b431
1358237631a934c
1424553bbd8bc7b
151026449622a61
hex7745b90bd9a5

131141341010341 has 2 divisors, whose sum is σ = 131141341010342. Its totient is φ = 131141341010340.

The previous prime is 131141341010299. The next prime is 131141341010501. The reversal of 131141341010341 is 143010143141131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104221026676900 + 26920314333441 = 10208870^2 + 5188479^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141341010341 - 219 = 131141340486053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141341017341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570670505170 + 65570670505171.

It is an arithmetic number, because the mean of its divisors is an integer number (65570670505171).

Almost surely, 2131141341010341 is an apocalyptic number.

It is an amenable number.

131141341010341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141341010341 is an equidigital number, since it uses as much as digits as its factorization.

131141341010341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 131141341010341 its reverse (143010143141131), we get a palindrome (274151484151472).

The spelling of 131141341010341 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, ten thousand, three hundred forty-one".