Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000100011101000101011111 |
3 | 122012022222201120012211211211 |
4 | 131310112321010131011133 |
5 | 114142104431344321224 |
6 | 1142525300041125251 |
7 | 36423435456433255 |
oct | 3564267104350537 |
9 | 565288646184754 |
10 | 131141341401439 |
11 | 38870804411a96 |
12 | 128600a1a89827 |
13 | 58237632b5375 |
14 | 24553bc0505d5 |
15 | 102644969d894 |
hex | 7745b911d15f |
131141341401439 has 2 divisors, whose sum is σ = 131141341401440. Its totient is φ = 131141341401438.
The previous prime is 131141341401407. The next prime is 131141341401461. The reversal of 131141341401439 is 934104143141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131141341401439 - 25 = 131141341401407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141341401839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570670700719 + 65570670700720.
It is an arithmetic number, because the mean of its divisors is an integer number (65570670700720).
Almost surely, 2131141341401439 is an apocalyptic number.
131141341401439 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141341401439 is an equidigital number, since it uses as much as digits as its factorization.
131141341401439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 131141341401439 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, four hundred one thousand, four hundred thirty-nine".
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