Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0100101011110000001111 |
3 | 1201102200212120112102010011 |
4 | 2332311133110223300033 |
5 | 3204330221402143203 |
6 | 43520314501054051 |
7 | 2522315322164131 |
oct | 276653724536017 |
9 | 51380776472104 |
10 | 13114134412303 |
11 | 41a6744a99a81 |
12 | 15797350b7327 |
13 | 7418718a8922 |
14 | 334a2834b051 |
15 | 17b1de70576d |
hex | bed5f52bc0f |
13114134412303 has 2 divisors, whose sum is σ = 13114134412304. Its totient is φ = 13114134412302.
The previous prime is 13114134412297. The next prime is 13114134412307. The reversal of 13114134412303 is 30321443141131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114134412303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114134412307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067206151 + 6557067206152.
It is an arithmetic number, because the mean of its divisors is an integer number (6557067206152).
Almost surely, 213114134412303 is an apocalyptic number.
13114134412303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114134412303 is an equidigital number, since it uses as much as digits as its factorization.
13114134412303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 13114134412303 its reverse (30321443141131), we get a palindrome (43435577553434).
The spelling of 13114134412303 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twelve thousand, three hundred three".
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