13114140321731 has 2 divisors, whose sum is σ = 13114140321732. Its totient is φ = 13114140321730.

The previous prime is 13114140321719. The next prime is 13114140321743. The reversal of 13114140321731 is 13712304141131.

It is a balanced prime because it is at equal distance from previous prime (13114140321719) and next prime (13114140321743).

It is an emirp because it is prime and its reverse (13712304141131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13114140321731 is a prime.

It is a super-2 number, since 2×13114140321731² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13114140321761) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557070160865 + 6557070160866.

It is an arithmetic number, because the mean of its divisors is an integer number (6557070160866).

Almost surely, 2^{13114140321731} is an apocalyptic number.

13114140321731 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114140321731 is an equidigital number, since it uses as much as digits as its factorization.

13114140321731 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 13114140321731 its reverse (13712304141131), we get a palindrome (26826444462862).

The spelling of 13114140321731 in words is "thirteen trillion, one hundred fourteen billion, one hundred forty million, three hundred twenty-one thousand, seven hundred thirty-one".