Base | Representation |
---|---|
bin | 11101110100010110111100… |
… | …110011110010011001100111 |
3 | 122012022222212221021100120011 |
4 | 131310112330303302121213 |
5 | 114142110043430004114 |
6 | 1142525310201551051 |
7 | 36423440150631016 |
oct | 3564267463623147 |
9 | 565288787240504 |
10 | 131141404141159 |
11 | 388708368742a5 |
12 | 128600baaa5487 |
13 | 58237732b1369 |
14 | 24553c6502a7d |
15 | 102644ee431c4 |
hex | 7745bccf2667 |
131141404141159 has 2 divisors, whose sum is σ = 131141404141160. Its totient is φ = 131141404141158.
The previous prime is 131141404141103. The next prime is 131141404141271. The reversal of 131141404141159 is 951141404141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141404141159 - 215 = 131141404108391 is a prime.
It is a super-2 number, since 2×1311414041411592 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141404151159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570702070579 + 65570702070580.
It is an arithmetic number, because the mean of its divisors is an integer number (65570702070580).
Almost surely, 2131141404141159 is an apocalyptic number.
131141404141159 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141404141159 is an equidigital number, since it uses as much as digits as its factorization.
131141404141159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 40.
The spelling of 131141404141159 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred four million, one hundred forty-one thousand, one hundred fifty-nine".
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