Base | Representation |
---|---|
bin | 1011111011010110001101… |
… | …0011001010111000011111 |
3 | 1201102201001020001201212221 |
4 | 2332311203103022320133 |
5 | 3204330340441440013 |
6 | 43520325243010211 |
7 | 2522320062215032 |
oct | 276654323127037 |
9 | 51381036051787 |
10 | 13114201124383 |
11 | 41a6779714827 |
12 | 1579753509967 |
13 | 741882665a28 |
14 | 334a33155019 |
15 | 17b1e54d208d |
hex | bed634cae1f |
13114201124383 has 2 divisors, whose sum is σ = 13114201124384. Its totient is φ = 13114201124382.
The previous prime is 13114201124327. The next prime is 13114201124407. The reversal of 13114201124383 is 38342110241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114201124383 - 29 = 13114201123871 is a prime.
It is a super-2 number, since 2×131142011243832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114201124083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557100562191 + 6557100562192.
It is an arithmetic number, because the mean of its divisors is an integer number (6557100562192).
Almost surely, 213114201124383 is an apocalyptic number.
13114201124383 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114201124383 is an equidigital number, since it uses as much as digits as its factorization.
13114201124383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 34.
The spelling of 13114201124383 in words is "thirteen trillion, one hundred fourteen billion, two hundred one million, one hundred twenty-four thousand, three hundred eighty-three".
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