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131142098806177 is a prime number
BaseRepresentation
bin11101110100010111100110…
…001101101110010110100001
3122012100001200100101222211011
4131310113212031232112201
5114142113004243244202
61142525503135020521
736423463314322324
oct3564274615562641
9565301610358734
10131142098806177
11388710629aa418
121286027366a741
1358238541a3354
14245545088c7bb
151026490e0ebd7
hex7745e636e5a1

131142098806177 has 2 divisors, whose sum is σ = 131142098806178. Its totient is φ = 131142098806176.

The previous prime is 131142098806153. The next prime is 131142098806241. The reversal of 131142098806177 is 771608890241131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99926233608721 + 31215865197456 = 9996311^2 + 5587116^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142098806177 - 215 = 131142098773409 is a prime.

It is a super-2 number, since 2×1311420988061772 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131142098806877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571049403088 + 65571049403089.

It is an arithmetic number, because the mean of its divisors is an integer number (65571049403089).

Almost surely, 2131142098806177 is an apocalyptic number.

It is an amenable number.

131142098806177 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142098806177 is an equidigital number, since it uses as much as digits as its factorization.

131142098806177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4064256, while the sum is 58.

The spelling of 131142098806177 in words is "one hundred thirty-one trillion, one hundred forty-two billion, ninety-eight million, eight hundred six thousand, one hundred seventy-seven".