Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …010111000001011110011001 |
3 | 122012100001200111222211121112 |
4 | 131310113212113001132121 |
5 | 114142113010404300201 |
6 | 1142525503303150105 |
7 | 36423463344124154 |
oct | 3564274627013631 |
9 | 565301614884545 |
10 | 131142101243801 |
11 | 3887106431488a |
12 | 12860274445335 |
13 | 5823854847a2b |
14 | 2455450d24c9b |
15 | 10264912420bb |
hex | 7745e65c1799 |
131142101243801 has 2 divisors, whose sum is σ = 131142101243802. Its totient is φ = 131142101243800.
The previous prime is 131142101243729. The next prime is 131142101243807. The reversal of 131142101243801 is 108342101241131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96243261433225 + 34898839810576 = 9810365^2 + 5907524^2 .
It is a cyclic number.
It is not a de Polignac number, because 131142101243801 - 234 = 131124921374617 is a prime.
It is not a weakly prime, because it can be changed into another prime (131142101243807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571050621900 + 65571050621901.
It is an arithmetic number, because the mean of its divisors is an integer number (65571050621901).
Almost surely, 2131142101243801 is an apocalyptic number.
It is an amenable number.
131142101243801 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142101243801 is an equidigital number, since it uses as much as digits as its factorization.
131142101243801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 32.
Adding to 131142101243801 its reverse (108342101241131), we get a palindrome (239484202484932).
The spelling of 131142101243801 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred one million, two hundred forty-three thousand, eight hundred one".
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