Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …011011000001011111010001 |
3 | 122012100001200120222010001202 |
4 | 131310113212123001133101 |
5 | 114142113011141324213 |
6 | 1142525503341440545 |
7 | 36423463356052331 |
oct | 3564274633013721 |
9 | 565301616863052 |
10 | 131142102292433 |
11 | 38871064970721 |
12 | 12860274870155 |
13 | 5823854b2411b |
14 | 24554511190c1 |
15 | 102649139cb58 |
hex | 7745e66c17d1 |
131142102292433 has 2 divisors, whose sum is σ = 131142102292434. Its totient is φ = 131142102292432.
The previous prime is 131142102292429. The next prime is 131142102292483. The reversal of 131142102292433 is 334292201241131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127309857549889 + 3832244742544 = 11283167^2 + 1957612^2 .
It is a cyclic number.
It is not a de Polignac number, because 131142102292433 - 22 = 131142102292429 is a prime.
It is not a weakly prime, because it can be changed into another prime (131142102292483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051146216 + 65571051146217.
It is an arithmetic number, because the mean of its divisors is an integer number (65571051146217).
Almost surely, 2131142102292433 is an apocalyptic number.
It is an amenable number.
131142102292433 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142102292433 is an equidigital number, since it uses as much as digits as its factorization.
131142102292433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 131142102292433 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred two million, two hundred ninety-two thousand, four hundred thirty-three".
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