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131142102292483 is a prime number
BaseRepresentation
bin11101110100010111100110…
…011011000001100000000011
3122012100001200120222010010121
4131310113212123001200003
5114142113011141324413
61142525503341441111
736423463356052432
oct3564274633014003
9565301616863117
10131142102292483
1138871064970767
1212860274870197
135823854b24159
142455451119119
15102649139cb8d
hex7745e66c1803

131142102292483 has 2 divisors, whose sum is σ = 131142102292484. Its totient is φ = 131142102292482.

The previous prime is 131142102292433. The next prime is 131142102292493. The reversal of 131142102292483 is 384292201241131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131142102292483 is a prime.

It is not a weakly prime, because it can be changed into another prime (131142102292433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051146241 + 65571051146242.

It is an arithmetic number, because the mean of its divisors is an integer number (65571051146242).

Almost surely, 2131142102292483 is an apocalyptic number.

131142102292483 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142102292483 is an equidigital number, since it uses as much as digits as its factorization.

131142102292483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 43.

The spelling of 131142102292483 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred two million, two hundred ninety-two thousand, four hundred eighty-three".