Base | Representation |
---|---|
bin | 1011111011010110001111… |
… | …0110001011010111101110 |
3 | 1201102201001212022222102021 |
4 | 2332311203312023113232 |
5 | 3204330400314121142 |
6 | 43520330211420354 |
7 | 2522320233216166 |
oct | 276654366132756 |
9 | 51381055288367 |
10 | 13114210301422 |
11 | 41a678391265a |
12 | 15797565b46ba |
13 | 741884529b29 |
14 | 334a344635a6 |
15 | 17b1e61e6267 |
hex | bed63d8b5ee |
13114210301422 has 4 divisors (see below), whose sum is σ = 19671315452136. Its totient is φ = 6557105150710.
The previous prime is 13114210301383. The next prime is 13114210301441. The reversal of 13114210301422 is 22410301241131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278552575354 + ... + 3278552575357.
It is an arithmetic number, because the mean of its divisors is an integer number (4917828863034).
Almost surely, 213114210301422 is an apocalyptic number.
13114210301422 is a deficient number, since it is larger than the sum of its proper divisors (6557105150714).
13114210301422 is an equidigital number, since it uses as much as digits as its factorization.
13114210301422 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6557105150713.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13114210301422 its reverse (22410301241131), we get a palindrome (35524511542553).
The spelling of 13114210301422 in words is "thirteen trillion, one hundred fourteen billion, two hundred ten million, three hundred one thousand, four hundred twenty-two".
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