1311421535251 has 4 divisors (see below), whose sum is σ = 1311424881192. Its totient is φ = 1311418189312.

The previous prime is 1311421535111. The next prime is 1311421535269. The reversal of 1311421535251 is 1525351241131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311421535251 - 2⁹ = 1311421534739 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311421545251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 992905 + ... + 1899658.

It is an arithmetic number, because the mean of its divisors is an integer number (327856220298).

Almost surely, 2^{1311421535251} is an apocalyptic number.

1311421535251 is a deficient number, since it is larger than the sum of its proper divisors (3345941).

1311421535251 is an equidigital number, since it uses as much as digits as its factorization.

1311421535251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3345940.

The product of its digits is 18000, while the sum is 34.

Adding to 1311421535251 its reverse (1525351241131), we get a palindrome (2836772776382).

The spelling of 1311421535251 in words is "one trillion, three hundred eleven billion, four hundred twenty-one million, five hundred thirty-five thousand, two hundred fifty-one".