Base | Representation |
---|---|
bin | 10011000101010110110… |
… | …111111101010111010111 |
3 | 11122101000021212100200201 |
4 | 103011112313331113113 |
5 | 132441243132111002 |
6 | 2442243104121331 |
7 | 163514162424145 |
oct | 23052667752727 |
9 | 4571007770621 |
10 | 1311422535127 |
11 | 466197917971 |
12 | 1921b4906247 |
13 | 96888723673 |
14 | 4768a608595 |
15 | 241a6b2a087 |
hex | 13156dfd5d7 |
1311422535127 has 2 divisors, whose sum is σ = 1311422535128. Its totient is φ = 1311422535126.
The previous prime is 1311422535121. The next prime is 1311422535149. The reversal of 1311422535127 is 7215352241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311422535127 - 23 = 1311422535119 is a prime.
It is a super-2 number, since 2×13114225351272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311422535121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711267563 + 655711267564.
It is an arithmetic number, because the mean of its divisors is an integer number (655711267564).
Almost surely, 21311422535127 is an apocalyptic number.
1311422535127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311422535127 is an equidigital number, since it uses as much as digits as its factorization.
1311422535127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 50400, while the sum is 37.
Adding to 1311422535127 its reverse (7215352241131), we get a palindrome (8526774776258).
The spelling of 1311422535127 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred thirty-five thousand, one hundred twenty-seven".
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