13114231540051 has 2 divisors, whose sum is σ = 13114231540052. Its totient is φ = 13114231540050.

The previous prime is 13114231540043. The next prime is 13114231540061. The reversal of 13114231540051 is 15004513241131.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (15004513241131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13114231540051 - 2³ = 13114231540043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114231539995 and 13114231540022.

It is not a weakly prime, because it can be changed into another prime (13114231540001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557115770025 + 6557115770026.

It is an arithmetic number, because the mean of its divisors is an integer number (6557115770026).

Almost surely, 2^{13114231540051} is an apocalyptic number.

13114231540051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114231540051 is an equidigital number, since it uses as much as digits as its factorization.

13114231540051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 13114231540051 its reverse (15004513241131), we get a palindrome (28118744781182).

The spelling of 13114231540051 in words is "thirteen trillion, one hundred fourteen billion, two hundred thirty-one million, five hundred forty thousand, fifty-one".