Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …010111101010010000111 |
3 | 11122101000100100022000101 |
4 | 103011112322331102013 |
5 | 132441243332234343 |
6 | 2442243133024531 |
7 | 163514202210031 |
oct | 23052672752207 |
9 | 4571010308011 |
10 | 1311423321223 |
11 | 466198304534 |
12 | 1921b5025147 |
13 | 9688893a402 |
14 | 4768a770c51 |
15 | 241a6c32e4d |
hex | 13156ebd487 |
1311423321223 has 2 divisors, whose sum is σ = 1311423321224. Its totient is φ = 1311423321222.
The previous prime is 1311423321191. The next prime is 1311423321281. The reversal of 1311423321223 is 3221233241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311423321223 - 25 = 1311423321191 is a prime.
It is a super-2 number, since 2×13114233212232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311423321191 and 1311423321200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311423321293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711660611 + 655711660612.
It is an arithmetic number, because the mean of its divisors is an integer number (655711660612).
Almost surely, 21311423321223 is an apocalyptic number.
1311423321223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423321223 is an equidigital number, since it uses as much as digits as its factorization.
1311423321223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 28.
Adding to 1311423321223 its reverse (3221233241131), we get a palindrome (4532656562354).
The spelling of 1311423321223 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred twenty-one thousand, two hundred twenty-three".
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